What is the vertices 25x^2+16y^2+100x-96y=156 ?

The vertices 25x^2+16y^2+100x-96y=156 is (-2,8),(-2,-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices 25x^2+16y^2+100x-96y=156

vertices

25 x^{2} + 16 y^{2} + 100 x - 96 y = 156

(- 2, 8), (- 2, - 2)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

25 x^{2} + 16 y^{2} + 100 x - 96 y = 156 :

Ellipse with center

(h, k) = (- 2, 3), b = 5, a = 4

(- 2, 3 + 5), (- 2, 3 - 5)

Refine

(- 2, 8), (- 2, - 2)

300 x^{2} + 150 y^{2} = 50

\frac{x ^{2}}{169} + \frac{y ^{2}}{144} = 1

7 x^{2} + 16 y^{2} = 7

x^{2} + 4 y^{2} - 6 x + 8 y + 9 = 0

9 x^{2} + 25 y^{2} - 225 = 0

What is the vertices 25x^2+16y^2+100x-96y=156 ?
The vertices 25x^2+16y^2+100x-96y=156 is (-2,8),(-2,-2)