What is the vertices 100x^2+96y^2-8840=0 ?

The vertices 100x^2+96y^2-8840=0 is (0,(sqrt(1105))/(2sqrt(3))),(0,-(sqrt(1105))/(2sqrt(3)))

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vertices 100x^2+96y^2-8840=0

vertices

100 x^{2} + 96 y^{2} - 8840 = 0

(0, \frac{1105}{2 3}), (0, - \frac{1105}{2 3})

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

100 x^{2} + 96 y^{2} - 8840 = 0 :

Ellipse with center

(h, k) = (0, 0), b = \frac{1105}{2 3}, a = \frac{442}{5}

(0, 0 + \frac{1105}{2 3}), (0, 0 - \frac{1105}{2 3})

Refine

(0, \frac{1105}{2 3}), (0, - \frac{1105}{2 3})

\frac{( x - 3 ) ^{2}}{16} + \frac{( y + 1 ) ^{2}}{25} = 1

\frac{x ^{2}}{4} + \frac{( y + 2 ) ^{2}}{16} = 1

\frac{( x + 6 ) ^{2}}{36} + \frac{( y - 7 ) ^{2}}{32} = 1

16 x^{2} + 4 y^{2} + 96 x - 24 y + 116 = 0

\frac{( x - 4 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{64} = 1

What is the vertices 100x^2+96y^2-8840=0 ?
The vertices 100x^2+96y^2-8840=0 is (0,(sqrt(1105))/(2sqrt(3))),(0,-(sqrt(1105))/(2sqrt(3)))