What is the vertices 5x^2+9y^2-20x+54y+56=0 ?

The vertices 5x^2+9y^2-20x+54y+56=0 is (5,-3),(-1,-3)

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vertices 5x^2+9y^2-20x+54y+56=0

vertices

5 x^{2} + 9 y^{2} - 20 x + 54 y + 56 = 0

(5, - 3), (- 1, - 3)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

5 x^{2} + 9 y^{2} - 20 x + 54 y + 56 = 0 :

Ellipse with center

(h, k) = (2, - 3), a = 3, b = 5

(2 + 3, - 3), (2 - 3, - 3)

Refine

(5, - 3), (- 1, - 3)

\frac{x ^{2}}{5} + \frac{y ^{2}}{7} = 1

9 x^{2} + 36 y^{2} = 324

36 x^{2} + y^{2} = 36

\frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 1

9 x^{2} + 36 x + 9 y^{2} + 72 y + 155 = 0

What is the vertices 5x^2+9y^2-20x+54y+56=0 ?
The vertices 5x^2+9y^2-20x+54y+56=0 is (5,-3),(-1,-3)