What is the vertices 7x^2+9y^2-63=0 ?

The vertices 7x^2+9y^2-63=0 is (3,0),(-3,0)

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vertices 7x^2+9y^2-63=0

vertices

7 x^{2} + 9 y^{2} - 63 = 0

(3, 0), (- 3, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

7 x^{2} + 9 y^{2} - 63 = 0 :

Ellipse with center

(h, k) = (0, 0), a = 3, b = 7

(0 + 3, 0), (0 - 3, 0)

Refine

(3, 0), (- 3, 0)

\frac{5}{81} x^{2} + \frac{y ^{2}}{9} = 1

x^{2} + y^{2} = 1

x^{2} + 3 y^{2} - 4 x + 12 y + 13 = 0

16 x^{2} + 25 y^{2} + 64 x - 200 y + 64 = 0

2 x^{2} + y^{2} = 4

What is the vertices 7x^2+9y^2-63=0 ?
The vertices 7x^2+9y^2-63=0 is (3,0),(-3,0)