What is the foci x^2+16y^2-64=0 ?

The foci x^2+16y^2-64=0 is (2sqrt(15),0),(-2sqrt(15),0)

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foci x^2+16y^2-64=0

foci

x^{2} + 16 y^{2} - 64 = 0

(215, 0), (- 215, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

x^{2} + 16 y^{2} - 64 = 0 :

Ellipse with center

(h, k) = (0, 0), a = 8, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 8^{2} - 2^{2} : 215

(0 + 215, 0), (0 - 215, 0)

Refine

(215, 0), (- 215, 0)

18 x^{2} + 24 x + 12 y^{2} - 12 y = 1

x^{2} + 25 y^{2} = 25

x^{2} + 9 y^{2} + 6 x - 90 y + 225 = 0

x^{2} + 3 y^{2} - 4 x + 12 y + 13 = 0

49 x^{2} + 25 y^{2} = 1225

What is the foci x^2+16y^2-64=0 ?
The foci x^2+16y^2-64=0 is (2sqrt(15),0),(-2sqrt(15),0)