What is the foci (x^2)/(100)+(y^2)/(44)=1 ?

The foci (x^2)/(100)+(y^2)/(44)=1 is (2sqrt(14),0),(-2sqrt(14),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/(100)+(y^2)/(44)=1

foci

\frac{x ^{2}}{100} + \frac{y ^{2}}{44} = 1

(214, 0), (- 214, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{100} + \frac{y ^{2}}{44} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 10, b = 211

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1 0^{2} - (211)^{2} : 214

(0 + 214, 0), (0 - 214, 0)

Refine

(214, 0), (- 214, 0)

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{9} = 1

4 x^{2} + 8 y^{2} = 3

16 x^{2} + 4 y^{2} - 64 = 0

\frac{( x + 6 ) ^{2}}{7} + \frac{( y - 3 ) ^{2}}{16} = 1

\frac{( x - 4 ) ^{2}}{3} + \frac{y ^{2}}{9} = 1

What is the foci (x^2)/(100)+(y^2)/(44)=1 ?
The foci (x^2)/(100)+(y^2)/(44)=1 is (2sqrt(14),0),(-2sqrt(14),0)