What is the foci (x^2)/4+(y^2)/(13)=1 ?

The foci (x^2)/4+(y^2)/(13)=1 is (0,3),(0,-3)

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foci (x^2)/4+(y^2)/(13)=1

foci

\frac{x ^{2}}{4} + \frac{y ^{2}}{13} = 1

(0, 3), (0, - 3)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{4} + \frac{y ^{2}}{13} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 13, a = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 13^{2} - 2^{2} : 3

(0, 0 + 3), (0, 0 - 3)

Refine

(0, 3), (0, - 3)

\frac{( x - 3 ) ^{2}}{9} + \frac{( y + 2 ) ^{2}}{25} = 1

25 \frac{x ^{2}}{4} - 50 x + 100 y^{2} + 800 y + 1075 = 0

x^{2} + 16 y^{2} = 1

28 x^{2} + 64 y^{2} - 56 x - 420 = 0

\frac{( x + 1 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{10} = 1

What is the foci (x^2)/4+(y^2)/(13)=1 ?
The foci (x^2)/4+(y^2)/(13)=1 is (0,3),(0,-3)