What is the foci 36x^2+4y^2+360x-32y+820=0 ?

The foci 36x^2+4y^2+360x-32y+820=0 is (-5,4+4sqrt(2)),(-5,4-4sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 36x^2+4y^2+360x-32y+820=0

foci

36 x^{2} + 4 y^{2} + 360 x - 32 y + 820 = 0

(- 5, 4 + 42), (- 5, 4 - 42)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

36 x^{2} + 4 y^{2} + 360 x - 32 y + 820 = 0 :

Ellipse with center

(h, k) = (- 5, 4), b = 6, a = 2

(- 5, 4 + c), (- 5, 4 - c)

Compute

c :

c = 6^{2} - 2^{2} : 42

(- 5, 4 + 42), (- 5, 4 - 42)

\frac{( x - 1 ) ^{2}}{100} + \frac{( y - 2 ) ^{2}}{36} = 1

\frac{( x + 6 ) ^{2}}{4} + \frac{( y + 6 ) ^{2}}{25} = 1

\frac{( x + 2 ) ^{2}}{25} + \frac{( y - 5 ) ^{2}}{9} = 1

\frac{( x + 4 ) ^{2}}{24} + \frac{( y + 2 ) ^{2}}{49} = 1

3 x^{2} + 4 y^{2} = 48

What is the foci 36x^2+4y^2+360x-32y+820=0 ?
The foci 36x^2+4y^2+360x-32y+820=0 is (-5,4+4sqrt(2)),(-5,4-4sqrt(2))