What is the foci (x^2)/(32)+(y^2)/(18)=1 ?

The foci (x^2)/(32)+(y^2)/(18)=1 is (sqrt(14),0),(-sqrt(14),0)

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foci (x^2)/(32)+(y^2)/(18)=1

foci

\frac{x ^{2}}{32} + \frac{y ^{2}}{18} = 1

(14, 0), (- 14, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{32} + \frac{y ^{2}}{18} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 42, b = 32

(0 + c, 0), (0 - c, 0)

Compute

c :

c = (42)^{2} - (32)^{2} : 14

(0 + 14, 0), (0 - 14, 0)

Refine

(14, 0), (- 14, 0)

x^{2} + \frac{y ^{2}}{100} = 1

\frac{( x - 2 ) ^{2}}{8 ^{2}} + \frac{( y + 2 ) ^{2}}{3 ^{2}} = 1

y^{2} = 1 - 49 x^{2}

\frac{( x + 4 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{4} = 1

9 x^{2} + 49 y^{2} + 18 x + 294 y - 9 = 0

What is the foci (x^2)/(32)+(y^2)/(18)=1 ?
The foci (x^2)/(32)+(y^2)/(18)=1 is (sqrt(14),0),(-sqrt(14),0)