What is the foci 3x^2-6x+y^2+4y-11=0 ?

The foci 3x^2-6x+y^2+4y-11=0 is (1,-2+2sqrt(3)),(1,-2-2sqrt(3))

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foci 3x^2-6x+y^2+4y-11=0

foci

3 x^{2} - 6 x + y^{2} + 4 y - 11 = 0

(1, - 2 + 23), (1, - 2 - 23)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

3 x^{2} - 6 x + y^{2} + 4 y - 11 = 0 :

Ellipse with center

(h, k) = (1, - 2), b = 32, a = 6

(1, - 2 + c), (1, - 2 - c)

Compute

c :

c = (32)^{2} - 6^{2} : 23

(1, - 2 + 23), (1, - 2 - 23)

5 x^{2} + 2 y^{2} = 5

4 x^{2} + 8 x + 2 y^{2} + 16 y = - 28

x^{2} - 4 x + 100 y^{2} + 200 y + 4 = 0

\frac{( x + 1 ) ^{2}}{1} + \frac{( y - 2 ) ^{2}}{4} = 1

\frac{( x - 9 ) ^{2}}{4} + \frac{( y + 10 ) ^{2}}{81} = 1

What is the foci 3x^2-6x+y^2+4y-11=0 ?
The foci 3x^2-6x+y^2+4y-11=0 is (1,-2+2sqrt(3)),(1,-2-2sqrt(3))