What is the foci 25x^2+9y^2+150x=0 ?

The foci 25x^2+9y^2+150x=0 is (-3,4),(-3,-4)

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foci 25x^2+9y^2+150x=0

foci

25 x^{2} + 9 y^{2} + 150 x = 0

(- 3, 4), (- 3, - 4)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

25 x^{2} + 9 y^{2} + 150 x = 0 :

Ellipse with center

(h, k) = (- 3, 0), b = 5, a = 3

(- 3, 0 + c), (- 3, 0 - c)

Compute

c :

c = 5^{2} - 3^{2} : 4

(- 3, 0 + 4), (- 3, 0 - 4)

Refine

(- 3, 4), (- 3, - 4)

4 x^{2} + y^{2} - 4 y = 0

\frac{( x + 3 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{16} = 1

\frac{( x - 6 ) ^{2}}{36} + \frac{( y + 4 ) ^{2}}{16} = 1

1 = \frac{( x - 2 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{25}

\frac{( x - 1 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{1} = 1

What is the foci 25x^2+9y^2+150x=0 ?
The foci 25x^2+9y^2+150x=0 is (-3,4),(-3,-4)