What is the foci 9x^2+6y^2+36y=0 ?

The foci 9x^2+6y^2+36y=0 is (0,-3+sqrt(3)),(0,-3-sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 9x^2+6y^2+36y=0

foci

9 x^{2} + 6 y^{2} + 36 y = 0

(0, - 3 + 3), (0, - 3 - 3)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

9 x^{2} + 6 y^{2} + 36 y = 0 :

Ellipse with center

(h, k) = (0, - 3), b = 3, a = 6

(0, - 3 + c), (0, - 3 - c)

Compute

c :

c = 3^{2} - 6^{2} : 3

(0, - 3 + 3), (0, - 3 - 3)

\frac{( x - 1 ) ^{2}}{12} + \frac{y ^{2}}{8} = 100

\frac{x ^{2}}{64} + \frac{y ^{2}}{81} = 1

x^{2} + y^{2} - 8 x - 20 y + 115 = 0

9 x^{2} + 16 y^{2} - 18 x - 64 y - 71 = 0

\frac{x ^{2}}{16} + \frac{y ^{2}}{5} = 1

What is the foci 9x^2+6y^2+36y=0 ?
The foci 9x^2+6y^2+36y=0 is (0,-3+sqrt(3)),(0,-3-sqrt(3))