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Popular >

foci 5x^2+7y^2-35=0

Solution

foci

5 x^{2} + 7 y^{2} - 35 = 0

Solution

(2, 0), (- 2, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

5 x^{2} + 7 y^{2} - 35 = 0 :

Ellipse with center

(h, k) = (0, 0), a = 7, b = 5

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 7^{2} - 5^{2} : 2

(0 + 2, 0), (0 - 2, 0)

Refine

(2, 0), (- 2, 0)

Popular Examples

foci 4(x-1)^2+13(y+3)^2=52 foci

4 (x - 1)^{2} + 13 (y + 3)^{2} = 52

foci x^2+5y^2-4x+20y=-19 foci

x^{2} + 5 y^{2} - 4 x + 20 y = - 19

foci ((x-1)^2)/5+((y+1)^2)/9 =1 foci

\frac{( x - 1 ) ^{2}}{5} + \frac{( y + 1 ) ^{2}}{9} = 1

foci x^2+(y^2)/9 =1 foci

x^{2} + \frac{y ^{2}}{9} = 1

foci ((x-2)^2)/(64)+((y-4)^2)/(16)=1 foci

\frac{( x - 2 ) ^{2}}{64} + \frac{( y - 4 ) ^{2}}{16} = 1

Frequently Asked Questions (FAQ)

What is the foci 5x^2+7y^2-35=0 ?
The foci 5x^2+7y^2-35=0 is (sqrt(2),0),(-sqrt(2),0)