What is the foci 16x^2+36y^2=576 ?

The foci 16x^2+36y^2=576 is (2sqrt(5),0),(-2sqrt(5),0)

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foci 16x^2+36y^2=576

foci

16 x^{2} + 36 y^{2} = 576

(25, 0), (- 25, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

16 x^{2} + 36 y^{2} = 576 :

Ellipse with center

(h, k) = (0, 0), a = 6, b = 4

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 6^{2} - 4^{2} : 25

(0 + 25, 0), (0 - 25, 0)

Refine

(25, 0), (- 25, 0)

1 x^{2} + 3 y^{2} + 9 x + 8 y - 14 = 0

\frac{( x + 3 ) ^{2}}{6 ^{2}} + \frac{( y + 7 ) ^{2}}{2 ^{2}} = 1

\frac{( x + 5 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{4} = 1

\frac{( x + 3 ) ^{2}}{9} + \frac{( y - 5 ) ^{2}}{3} = 1

(x + 2)^{2} + \frac{( y + 4 ) ^{2}}{\frac{1}{4}} = 1

What is the foci 16x^2+36y^2=576 ?
The foci 16x^2+36y^2=576 is (2sqrt(5),0),(-2sqrt(5),0)