What is the foci (x^2)/(81)+(y^2)/(56)=1 ?

The foci (x^2)/(81)+(y^2)/(56)=1 is (5,0),(-5,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/(81)+(y^2)/(56)=1

foci

\frac{x ^{2}}{81} + \frac{y ^{2}}{56} = 1

(5, 0), (- 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{81} + \frac{y ^{2}}{56} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 9, b = 214

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 9^{2} - (214)^{2} : 5

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

x^{2} - 4 x + 9 y^{2} + 54 y + 4 = 0

x^{2} + 4 x + 4 y^{2} - 8 y + 4 = 0

x^{2} + 5 y^{2} - 2 x + 10 y = - 1

(\frac{x}{8})^{2} + (\frac{y}{6})^{2} = 1

\frac{x ^{2}}{484} + \frac{y ^{2}}{289} = 1

What is the foci (x^2)/(81)+(y^2)/(56)=1 ?
The foci (x^2)/(81)+(y^2)/(56)=1 is (5,0),(-5,0)