What is the foci (x^2)/(100)+((y-6)^2)/(64)=1 ?

The foci (x^2)/(100)+((y-6)^2)/(64)=1 is (6,6),(-6,6)

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foci (x^2)/(100)+((y-6)^2)/(64)=1

foci

\frac{x ^{2}}{100} + \frac{( y - 6 ) ^{2}}{64} = 1

(6, 6), (- 6, 6)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{100} + \frac{( y - 6 ) ^{2}}{64} = 1 :

Ellipse with center

(h, k) = (0, 6), a = 10, b = 8

(0 + c, 6), (0 - c, 6)

Compute

c :

c = 1 0^{2} - 8^{2} : 6

(0 + 6, 6), (0 - 6, 6)

Refine

(6, 6), (- 6, 6)

6 x^{2} + 9 y^{2} - 18 y - 45 = 0

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 2 ) ^{2}}{5} = 1

\frac{( x - 1 ) ^{2}}{9} + \frac{y ^{2}}{4} = 1

4 x^{2} + 9 y^{2} + 16 x - 90 y + 205 = 0

9 x^{2} + 4 y^{2} - 18 x - 16 y - 11 = 0

What is the foci (x^2)/(100)+((y-6)^2)/(64)=1 ?
The foci (x^2)/(100)+((y-6)^2)/(64)=1 is (6,6),(-6,6)