What is the foci (x^2)/(46)+((y+8)^2)/(26)=1 ?

The foci (x^2)/(46)+((y+8)^2)/(26)=1 is (2sqrt(5),-8),(-2sqrt(5),-8)

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foci (x^2)/(46)+((y+8)^2)/(26)=1

foci

\frac{x ^{2}}{46} + \frac{( y + 8 ) ^{2}}{26} = 1

(25, - 8), (- 25, - 8)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{46} + \frac{( y + 8 ) ^{2}}{26} = 1 :

Ellipse with center

(h, k) = (0, - 8), a = 46, b = 26

(0 + c, - 8), (0 - c, - 8)

Compute

c :

c = 46^{2} - 26^{2} : 25

(0 + 25, - 8), (0 - 25, - 8)

Refine

(25, - 8), (- 25, - 8)

2 x^{2} + 3 y^{2} + 4 x - 6 y - 1 = 0

\frac{x ^{2}}{15} + \frac{( y - 5 ) ^{2}}{20} = 1

x^{2} + 9 y^{2} - 8 x + 18 y - 11 = 0

4 x^{2} + 36 y^{2} - 24 x - 288 y + 611 = 0

\frac{( x - 1 ) ^{2}}{12} + \frac{( y - 2 ) ^{2}}{8} = 1

What is the foci (x^2)/(46)+((y+8)^2)/(26)=1 ?
The foci (x^2)/(46)+((y+8)^2)/(26)=1 is (2sqrt(5),-8),(-2sqrt(5),-8)