What is the foci 64x^2+16y^2=1024 ?

The foci 64x^2+16y^2=1024 is (0,4sqrt(3)),(0,-4sqrt(3))

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foci 64x^2+16y^2=1024

foci

64 x^{2} + 16 y^{2} = 1024

(0, 43), (0, - 43)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

64 x^{2} + 16 y^{2} = 1024 :

Ellipse with center

(h, k) = (0, 0), b = 8, a = 4

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 8^{2} - 4^{2} : 43

(0, 0 + 43), (0, 0 - 43)

Refine

(0, 43), (0, - 43)

16 x^{2} + 36 y^{2} + 192 x - 288 y + 576 = 0

4 x^{2} - 8 x + y^{2} + 4 y - 92 = 0

\frac{x ^{2}}{9} + (y - 1)^{2} = 1

\frac{x ^{2}}{8} + \frac{y ^{2}}{24} = 1

\frac{( x - 2 ) ^{2}}{49} + \frac{( y + 1 ) ^{2}}{25} = 1

What is the foci 64x^2+16y^2=1024 ?
The foci 64x^2+16y^2=1024 is (0,4sqrt(3)),(0,-4sqrt(3))