What is the foci 25x^2+9y^2+100x-125=0 ?

The foci 25x^2+9y^2+100x-125=0 is (-2,4),(-2,-4)

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foci 25x^2+9y^2+100x-125=0

foci

25 x^{2} + 9 y^{2} + 100 x - 125 = 0

(- 2, 4), (- 2, - 4)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

25 x^{2} + 9 y^{2} + 100 x - 125 = 0 :

Ellipse with center

(h, k) = (- 2, 0), b = 5, a = 3

(- 2, 0 + c), (- 2, 0 - c)

Compute

c :

c = 5^{2} - 3^{2} : 4

(- 2, 0 + 4), (- 2, 0 - 4)

Refine

(- 2, 4), (- 2, - 4)

4 x^{2} + 25 y^{2} - 40 x + 150 y + 225 = 0

\frac{( x - 8 ) ^{2}}{64} + \frac{( y - 5 ) ^{2}}{5 ^{2}} = 1

2 x^{2} + 2 y^{2} - 28 x + 12 y + 114 = 0

25 x^{2} + 64 y^{2} = 1600

\frac{( x + 2 ) ^{2}}{22} + \frac{( y + 3 ) ^{2}}{18} = 1

What is the foci 25x^2+9y^2+100x-125=0 ?
The foci 25x^2+9y^2+100x-125=0 is (-2,4),(-2,-4)