What is the foci 16x^2+25y^2-224x+250y=191 ?

The foci 16x^2+25y^2-224x+250y=191 is (13,-5),(1,-5)

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foci 16x^2+25y^2-224x+250y=191

foci

16 x^{2} + 25 y^{2} - 224 x + 250 y = 191

(13, - 5), (1, - 5)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

16 x^{2} + 25 y^{2} - 224 x + 250 y = 191 :

Ellipse with center

(h, k) = (7, - 5), a = 10, b = 8

(7 + c, - 5), (7 - c, - 5)

Compute

c :

c = 1 0^{2} - 8^{2} : 6

(7 + 6, - 5), (7 - 6, - 5)

Refine

(13, - 5), (1, - 5)

\frac{( x - 1 ) ^{2}}{40} + \frac{( y + 4 ) ^{2}}{36} = 1

\frac{x ^{2}}{( \frac{5}{2} ) ^{2}} + \frac{y ^{2}}{( \frac{3}{2} ) ^{2}} = 1

x^{2} + 4 y^{2} - 6 x + 8 y - 3 = 0

\frac{x ^{2}}{36} + \frac{y ^{2}}{121} = 1

2 x^{2} + y^{2} + 12 x - 2 y + 11 = 0

What is the foci 16x^2+25y^2-224x+250y=191 ?
The foci 16x^2+25y^2-224x+250y=191 is (13,-5),(1,-5)