What is the foci (x^2)/4+(y^2)/1 =1 ?

The foci (x^2)/4+(y^2)/1 =1 is (sqrt(3),0),(-sqrt(3),0)

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foci (x^2)/4+(y^2)/1 =1

foci

\frac{x ^{2}}{4} + \frac{y ^{2}}{1} = 1

(3, 0), (- 3, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{4} + \frac{y ^{2}}{1} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 2, b = 1

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} - 1^{2} : 3

(0 + 3, 0), (0 - 3, 0)

Refine

(3, 0), (- 3, 0)

16 x^{2} + 4 y^{2} + 96 x - 24 y + 116 = 0

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

\frac{( x ^{2} )}{16} + \frac{( y ^{2} )}{36} = 1

x^{2} + 4 y^{2} + 10 x + 8 y - 3 = 0

36 x^{2} + y^{2} = 36

What is the foci (x^2)/4+(y^2)/1 =1 ?
The foci (x^2)/4+(y^2)/1 =1 is (sqrt(3),0),(-sqrt(3),0)