What is the center 25x^2+144y^2=900 ?

The center 25x^2+144y^2=900 is (0,0)

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center 25x^2+144y^2=900

center

25 x^{2} + 144 y^{2} = 900

(0, 0)

Solution steps

25 x^{2} + 144 y^{2} = 900

Rewrite

25 x^{2} + 144 y^{2} = 900

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{5}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = \frac{5}{2}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 6, b = \frac{5}{2}

And the center is:

(0, 0)

x^{2} + 4 \cdot y^{2} - 4 \cdot y = 0

36 x^{2} + 288 x + 64 y^{2} - 256 y = 1472

16 x^{2} + 25 y^{2} = 400

x^{2} + 4 y^{2} + 7 = 12 y - 2 x

2 x^{2} + y^{2} + 4 x = 4