What is the center 2x^2+y^2=50 ?

The center 2x^2+y^2=50 is (0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

center 2x^2+y^2=50

center

2 x^{2} + y^{2} = 50

(0, 0)

Solution steps

2 x^{2} + y^{2} = 50

Rewrite

2 x^{2} + y^{2} = 50

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{( 5 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 52

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 52, a = 5

And the center is:

(0, 0)

4 x^{2} + y^{2} = 16

\frac{( x - h ) ^{2}}{a ^{2}} + \frac{( y - k ) ^{2}}{b ^{2}} = 1

16 (x - 1)^{2} + 9 (y + 2)^{2} = 144

\frac{( x - 3 ) ^{2}}{16} + \frac{( y - 4 ) ^{2}}{9} = 1

4 x^{2} + y^{2} = 4