What is the center 36x^2+25y^2=900 ?

The center 36x^2+25y^2=900 is (0,0)

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center 36x^2+25y^2=900

center

36 x^{2} + 25 y^{2} = 900

(0, 0)

Solution steps

36 x^{2} + 25 y^{2} = 900

Rewrite

36 x^{2} + 25 y^{2} = 900

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 6, a = 5

And the center is:

(0, 0)

16 x^{2} + 25 y^{2} + 32 x - 384 = 0

25 x^{2} + 9 y^{2} - 150 x - 18 y + 9 = 0

\frac{( x + 2 ) ^{2}}{25} + \frac{( y - 4 ) ^{2}}{4} = 1

4 x^{2} + y^{2} - 48 x + 4 y + 48 = 0

\frac{x ^{2}}{64} + \frac{y ^{2}}{16} = 1