What is the center 9x^2-36x+4y^2=0 ?

The center 9x^2-36x+4y^2=0 is (2,0)

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center 9x^2-36x+4y^2=0

center

9 x^{2} - 36 x + 4 y^{2} = 0

(2, 0)

Solution steps

9 x^{2} - 36 x + 4 y^{2} = 0

Rewrite

9 x^{2} - 36 x + 4 y^{2} = 0

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 0), a = 2, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, 0), b = 3, a = 2

And the center is:

(2, 0)

3 (x + 1)^{2} + (y - 1)^{2} = 6

4 x^{2} + 2 y^{2} + 2 x - 8 y + 7 = 0

\frac{( x - 3 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{81} = 1

\frac{( x - 1 ) ^{2}}{36} + \frac{( y + 2 ) ^{2}}{25} = 1

25 x^{2} + 4 y^{2} - 50 x + 16 y - 59 = 0