What is the center x^2+4y^2=36 ?

The center x^2+4y^2=36 is (0,0)

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center x^2+4y^2=36

center

x^{2} + 4 y^{2} = 36

(0, 0)

Solution steps

x^{2} + 4 y^{2} = 36

Rewrite

x^{2} + 4 y^{2} = 36

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 6, b = 3

And the center is:

(0, 0)

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4 x^{2} + y^{2} + 12 x + 6 y + 5 = 0

x^{2} + 5 y^{2} - 4 x + 20 y = - 19

\frac{( x + 4 ) ^{2}}{9} + \frac{( y - 4 ) ^{2}}{25} = 1

16 x^{2} + 9 y^{2} - 64 x - 54 y + 1 = 0