What is the center ((x-3)^2)/(86)+((y+5)^2)/(49)=1 ?

The center ((x-3)^2)/(86)+((y+5)^2)/(49)=1 is (3,-5)

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center ((x-3)^2)/(86)+((y+5)^2)/(49)=1

center

\frac{( x - 3 ) ^{2}}{86} + \frac{( y + 5 ) ^{2}}{49} = 1

(3, - 5)

Solution steps

\frac{( x - 3 ) ^{2}}{86} + \frac{( y + 5 ) ^{2}}{49} = 1

Rewrite

\frac{( x - 3 ) ^{2}}{86} + \frac{( y + 5 ) ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 3 ) ^{2}}{( 86 ) ^{2}} + \frac{( y - ( - 5 ) ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (3, - 5), a = 86, b = 7

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (3, - 5), a = 86, b = 7

And the center is:

(3, - 5)

x^{2} + y^{2} - 6 y = 0

4 (x + 5)^{2} + 8 (y - 2)^{2} = 32

4 x^{2} + 9 y^{2} + 24 x + 18 y + 9 = 0

\frac{( x - 1 ) ^{2}}{2} + \frac{y ^{2}}{1} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 1

What is the center ((x-3)^2)/(86)+((y+5)^2)/(49)=1 ?
The center ((x-3)^2)/(86)+((y+5)^2)/(49)=1 is (3,-5)