What is the center ((x+1)^2)/(25)+((y-4)^2)/(169)=1 ?

The center ((x+1)^2)/(25)+((y-4)^2)/(169)=1 is (-1,4)

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center ((x+1)^2)/(25)+((y-4)^2)/(169)=1

center

\frac{( x + 1 ) ^{2}}{25} + \frac{( y - 4 ) ^{2}}{169} = 1

(- 1, 4)

Solution steps

\frac{( x + 1 ) ^{2}}{25} + \frac{( y - 4 ) ^{2}}{169} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{25} + \frac{( y - 4 ) ^{2}}{169} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{5 ^{2}} + \frac{( y - 4 ) ^{2}}{1 3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 4), a = 5, b = 13

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, 4), b = 13, a = 5

And the center is:

(- 1, 4)

4 x^{2} + 7 y^{2} < 28

\frac{( x + 4 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{16} = 1

16 x^{2} + 25 y^{2} - 64 x + 150 y - 11 = 0

\frac{( x - 2 ) ^{2}}{64} + \frac{( y + 4 ) ^{2}}{16} = 1

x^{2} + \frac{y ^{2}}{9} = 1

What is the center ((x+1)^2)/(25)+((y-4)^2)/(169)=1 ?
The center ((x+1)^2)/(25)+((y-4)^2)/(169)=1 is (-1,4)