What is the center ((x-1)^2)/(100)+((y-2)^2)/(36)=1 ?

The center ((x-1)^2)/(100)+((y-2)^2)/(36)=1 is (1,2)

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center ((x-1)^2)/(100)+((y-2)^2)/(36)=1

center

\frac{( x - 1 ) ^{2}}{100} + \frac{( y - 2 ) ^{2}}{36} = 1

(1, 2)

Solution steps

\frac{( x - 1 ) ^{2}}{100} + \frac{( y - 2 ) ^{2}}{36} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{100} + \frac{( y - 2 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{1 0 ^{2}} + \frac{( y - 2 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 2), a = 10, b = 6

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 2), a = 10, b = 6

And the center is:

(1, 2)

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

4 x^{2} + 5 y^{2} - 2 x + 78 y - 83 = x - 3 y + 3

135 x^{2} + 256 y^{2} - 34560 = 0

9 x^{2} + 4 y^{2} = 25

9 x^{2} + 25 y^{2} + 108 x - 200 y + 499 = 0

What is the center ((x-1)^2)/(100)+((y-2)^2)/(36)=1 ?
The center ((x-1)^2)/(100)+((y-2)^2)/(36)=1 is (1,2)