What is the eccentricity (x^2)/9+(y^2)/(25)=1 ?

The eccentricity (x^2)/9+(y^2)/(25)=1 is 4/5

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eccentricity (x^2)/9+(y^2)/(25)=1

eccentricity

\frac{x ^{2}}{9} + \frac{y ^{2}}{25} = 1

\frac{4}{5}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{9} + \frac{y ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 3

= \frac{5 ^{2} - 3 ^{2}}{5}

\frac{5 ^{2} - 3 ^{2}}{5} = \frac{4}{5}

= \frac{4}{5}

25 x^{2} + 16 y^{2} = 400

x^{2} + 4 y^{2} - 6 x - 16 y + 21 = 0

\frac{x ^{2}}{16} + \frac{y ^{2}}{12} = 1

x^{2} + 3 y^{2} = 1

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} > 1

What is the eccentricity (x^2)/9+(y^2)/(25)=1 ?
The eccentricity (x^2)/9+(y^2)/(25)=1 is 4/5