What is the eccentricity (x^2)/(36)+(y^2)/(49)=1 ?

The eccentricity (x^2)/(36)+(y^2)/(49)=1 is (sqrt(13))/7

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eccentricity (x^2)/(36)+(y^2)/(49)=1

eccentricity

\frac{x ^{2}}{36} + \frac{y ^{2}}{49} = 1

\frac{13}{7}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{36} + \frac{y ^{2}}{49} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 7, a = 6

= \frac{7 ^{2} - 6 ^{2}}{7}

\frac{7 ^{2} - 6 ^{2}}{7} = \frac{13}{7}

= \frac{13}{7}

\frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1

x^{2} + 2 y^{2} = 2

+ 36 x^{2} + y^{2} = 36

(x - 1)^{2} + (y - 2)^{2} = 30

\frac{x ^{2}}{16} + \frac{y ^{2}}{7} = 1

What is the eccentricity (x^2)/(36)+(y^2)/(49)=1 ?
The eccentricity (x^2)/(36)+(y^2)/(49)=1 is (sqrt(13))/7