What is the eccentricity x^2+4y^2-16=0 ?

The eccentricity x^2+4y^2-16=0 is (sqrt(3))/2

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eccentricity x^2+4y^2-16=0

eccentricity

x^{2} + 4 y^{2} - 16 = 0

\frac{3}{2}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

x^{2} + 4 y^{2} - 16 = 0 :

Ellipse with center

(h, k) = (0, 0), a = 4, b = 2

= \frac{4 ^{2} - 2 ^{2}}{4}

\frac{4 ^{2} - 2 ^{2}}{4} = \frac{3}{2}

= \frac{3}{2}

36 x^{2} + 9 y^{2} = 324

\frac{x ^{2}}{3} + \frac{y ^{2}}{5} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

14 x^{2} + 9 y^{2} = 126

10 x^{2} + 3 y^{2} = 30

What is the eccentricity x^2+4y^2-16=0 ?
The eccentricity x^2+4y^2-16=0 is (sqrt(3))/2