What is the eccentricity (y^2)/(64)+(x^2)/(36)=1 ?

The eccentricity (y^2)/(64)+(x^2)/(36)=1 is (sqrt(7))/4

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eccentricity (y^2)/(64)+(x^2)/(36)=1

eccentricity

\frac{y ^{2}}{64} + \frac{x ^{2}}{36} = 1

\frac{7}{4}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{y ^{2}}{64} + \frac{x ^{2}}{36} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 8, a = 6

= \frac{8 ^{2} - 6 ^{2}}{8}

\frac{8 ^{2} - 6 ^{2}}{8} = \frac{7}{4}

= \frac{7}{4}

3 x^{2} + y^{2} + 2 x - 6 y = 3

3 x^{2} + 12 x + 4 y^{2} - 40 y + 100 = 0

4 x^{2} + 9 y^{2} + 32 x - 18 y + 37 = 0

25 x^{2} + 9 y^{2} = 225

5 x^{2} + 7 y^{2} = 70

What is the eccentricity (y^2)/(64)+(x^2)/(36)=1 ?
The eccentricity (y^2)/(64)+(x^2)/(36)=1 is (sqrt(7))/4