What is the eccentricity (x^2)/9+(y^2)/(16)=1 ?

The eccentricity (x^2)/9+(y^2)/(16)=1 is (sqrt(7))/4

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eccentricity (x^2)/9+(y^2)/(16)=1

eccentricity

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

\frac{7}{4}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 4, a = 3

= \frac{4 ^{2} - 3 ^{2}}{4}

\frac{4 ^{2} - 3 ^{2}}{4} = \frac{7}{4}

= \frac{7}{4}

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1

8 x^{2} + 2 y^{2} = 16

2 x^{2} + y^{2} - 8 y - 2 x + 1 = 0

\frac{x ^{2}}{36} + \frac{y ^{2}}{81} = 1

\frac{1}{5} x^{2} + \frac{1}{125} y^{2} = 5

What is the eccentricity (x^2)/9+(y^2)/(16)=1 ?
The eccentricity (x^2)/9+(y^2)/(16)=1 is (sqrt(7))/4