What is the eccentricity (x^2)/4+(y^2)/1 =1 ?

The eccentricity (x^2)/4+(y^2)/1 =1 is (sqrt(3))/2

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eccentricity (x^2)/4+(y^2)/1 =1

eccentricity

\frac{x ^{2}}{4} + \frac{y ^{2}}{1} = 1

\frac{3}{2}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{4} + \frac{y ^{2}}{1} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 2, b = 1

= \frac{2 ^{2} - 1 ^{2}}{2}

\frac{2 ^{2} - 1 ^{2}}{2} = \frac{3}{2}

= \frac{3}{2}

\frac{( x ) ^{2}}{12} + \frac{( y ) ^{2}}{16} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

9 x^{2} + 49 y^{2} = 441

\frac{x ^{2}}{324} + \frac{y ^{2}}{400} = 1

\frac{x ^{2}}{1} + \frac{y ^{2}}{1} = 1

What is the eccentricity (x^2)/4+(y^2)/1 =1 ?
The eccentricity (x^2)/4+(y^2)/1 =1 is (sqrt(3))/2