What is the eccentricity (x^2)/5+(y^2)/(4.58)=1 ?

The eccentricity (x^2)/5+(y^2)/(4.58)=1 is 0.28982…

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eccentricity (x^2)/5+(y^2)/(4.58)=1

eccentricity

\frac{x ^{2}}{5} + \frac{y ^{2}}{4.58} = 1

0.28982 \dots

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{5} + \frac{y ^{2}}{4.58} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 5, b = 4.58

= \frac{( 5 ) ^{2} - ( 4.58 ) ^{2}}{5}

\frac{( 5 ) ^{2} - ( 4.58 ) ^{2}}{5} = 0.28982 \dots

= 0.28982 \dots

3 x^{2} + 2 y^{2} - 12 x + 8 y + 19 = 0

\frac{x ^{2}}{196} + \frac{y ^{2}}{121} = 1

\frac{x ^{2}}{5} + \frac{y ^{2}}{20.98} = 1

16 x^{2} + 192 x + 576 + 25 y^{2} = 1600

x^{2} + y^{2} = 1

What is the eccentricity (x^2)/5+(y^2)/(4.58)=1 ?
The eccentricity (x^2)/5+(y^2)/(4.58)=1 is 0.28982…