What is the eccentricity (x^2)/4+(y^2)/3 =1 ?

The eccentricity (x^2)/4+(y^2)/3 =1 is 1/2

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eccentricity (x^2)/4+(y^2)/3 =1

eccentricity

\frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 1

\frac{1}{2}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 2, b = 3

= \frac{2 ^{2} - ( 3 ) ^{2}}{2}

\frac{2 ^{2} - ( 3 ) ^{2}}{2} = \frac{1}{2}

= \frac{1}{2}

\frac{x ^{2}}{169} + \frac{y ^{2}}{25} = 1

16 x^{2} + 9 y^{2} + 160 x - 72 y + 544 = 144

\frac{x ^{2}}{25} + \frac{y ^{2}}{64} = 1

x^{2} + 9 y^{2} + 16 x + 18 y + 64 = 0

x^{2} + 42 y^{2} = 42

What is the eccentricity (x^2)/4+(y^2)/3 =1 ?
The eccentricity (x^2)/4+(y^2)/3 =1 is 1/2