What is the eccentricity 9x^2+4y^2-18x+8y-23=0 ?

The eccentricity 9x^2+4y^2-18x+8y-23=0 is (sqrt(5))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

eccentricity 9x^2+4y^2-18x+8y-23=0

eccentricity

9 x^{2} + 4 y^{2} - 18 x + 8 y - 23 = 0

\frac{5}{3}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

9 x^{2} + 4 y^{2} - 18 x + 8 y - 23 = 0 :

Ellipse with center

(h, k) = (1, - 1), b = 3, a = 2

= \frac{3 ^{2} - 2 ^{2}}{3}

\frac{3 ^{2} - 2 ^{2}}{3} = \frac{5}{3}

= \frac{5}{3}

\frac{( x - 1 ) ^{2}}{2} + \frac{y ^{2}}{1} = 1

\frac{x ^{2}}{64} + \frac{y ^{2}}{16} = 1

\frac{( x - 3 ) ^{2}}{2} + \frac{( y - 4 ) ^{2}}{4} = 1

8 x^{2} + 4 y^{2} + 16 x - 12 y - 15 = 0

\frac{( x ) ^{2}}{49} + \frac{( y ) ^{2}}{36} = 1

What is the eccentricity 9x^2+4y^2-18x+8y-23=0 ?
The eccentricity 9x^2+4y^2-18x+8y-23=0 is (sqrt(5))/3