What is the eccentricity x^2+(y^2)/4 =1 ?

The eccentricity x^2+(y^2)/4 =1 is (sqrt(3))/2

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eccentricity x^2+(y^2)/4 =1

eccentricity

x^{2} + \frac{y ^{2}}{4} = 1

\frac{3}{2}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

x^{2} + \frac{y ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 2, a = 1

= \frac{2 ^{2} - 1 ^{2}}{2}

\frac{2 ^{2} - 1 ^{2}}{2} = \frac{3}{2}

= \frac{3}{2}

x^{2} + 4 y^{2} = 46

+ x^{2} = 4 y - 2 y^{2}

\frac{( x + 5 ) ^{2}}{9} + (y - 1)^{2} = 1

36 x^{2} + 5 y^{2} - 90 y - 495 = 0

4 x^{2} + y^{2} = 4 x

What is the eccentricity x^2+(y^2)/4 =1 ?
The eccentricity x^2+(y^2)/4 =1 is (sqrt(3))/2