What is the axis (x^2)/(100)+(y^2)/(64)=1 ?

The axis (x^2)/(100)+(y^2)/(64)=1 is semi-major axis a=10, semi-minor axis b=8

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axis (x^2)/(100)+(y^2)/(64)=1

axis

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

semi - major axis a = 10, semi - minor axis b = 8

Solution steps

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

Rewrite

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 0 ^{2}} + \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 10, b = 8

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 10, b = 8

16 x^{2} + 25 y^{2} + 32 x - 384 = 0

\frac{x ^{2}}{49} + \frac{y ^{2}}{36} = 1

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

\frac{x ^{2}}{49} + \frac{y ^{2}}{9} = 1

\frac{x ^{2}}{8} + \frac{y ^{2}}{3} = 1

What is the axis (x^2)/(100)+(y^2)/(64)=1 ?
The axis (x^2)/(100)+(y^2)/(64)=1 is semi-major axis a=10, semi-minor axis b=8