What is the axis (x^2)/(4^2)+(y^2)/(3^2)=1 ?

The axis (x^2)/(4^2)+(y^2)/(3^2)=1 is semi-major axis a=4, semi-minor axis b=3

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axis (x^2)/(4^2)+(y^2)/(3^2)=1

axis

\frac{x ^{2}}{4 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

semi - major axis a = 4, semi - minor axis b = 3

Solution steps

\frac{x ^{2}}{4 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

Rewrite

\frac{x ^{2}}{4 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 3

81 x^{2} - 1296 x + 16 y^{2} + 64 y = - 3952

4 x^{2} + 9 y^{2} + 32 x - 18 y + 37 = 0

\frac{( x + 5 ) ^{2}}{25} + \frac{( y - 5 ) ^{2}}{16} = 1

9 x^{2} + 36 y^{2} + 36 x + 432 y = - 1008

6 x^{2} + 8 y^{2} + 12 x - 32 y = 178

What is the axis (x^2)/(4^2)+(y^2)/(3^2)=1 ?
The axis (x^2)/(4^2)+(y^2)/(3^2)=1 is semi-major axis a=4, semi-minor axis b=3