What is the axis 2x^2+7y^2=14 ?

The axis 2x^2+7y^2=14 is semi-major axis a=sqrt(7), semi-minor axis b=sqrt(2)

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axis 2x^2+7y^2=14

axis

2 x^{2} + 7 y^{2} = 14

semi - major axis a = 7, semi - minor axis b = 2

Solution steps

2 x^{2} + 7 y^{2} = 14

Rewrite

2 x^{2} + 7 y^{2} = 14

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 7 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 7, b = 2

5 x^{2} + 2 y^{2} = 10

x^{2} + 4 y^{2} - 6 x + 8 y + 9 = 0

2 x^{2} + y^{2} = 50

4 x^{2} + 2 y^{2} + 2 x - 8 y + 7 = 0

\frac{( x + 4 ) ^{2}}{9} + \frac{( y - 6 ) ^{2}}{25} = 1

What is the axis 2x^2+7y^2=14 ?
The axis 2x^2+7y^2=14 is semi-major axis a=sqrt(7), semi-minor axis b=sqrt(2)