What is the axis (x^2)/(36)+(y^2)/(100)=1 ?

The axis (x^2)/(36)+(y^2)/(100)=1 is semi-major axis b=10, semi-minor axis a=6

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axis (x^2)/(36)+(y^2)/(100)=1

axis

\frac{x ^{2}}{36} + \frac{y ^{2}}{100} = 1

semi - major axis b = 10, semi - minor axis a = 6

Solution steps

\frac{x ^{2}}{36} + \frac{y ^{2}}{100} = 1

Rewrite

\frac{x ^{2}}{36} + \frac{y ^{2}}{100} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{1 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = 10

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 10, a = 6

9 x^{2} + 25 y^{2} = 900

\frac{( x - 2 ) ^{2}}{36} + \frac{( y + 5 ) ^{2}}{9} = 1

25 x^{2} + 9 y^{2} - 100 x + 18 y - 116 = 0

x^{2} + y^{2} - y = 0

16 x^{2} + y^{2} - 64 x + 8 y + 16 = 0

What is the axis (x^2)/(36)+(y^2)/(100)=1 ?
The axis (x^2)/(36)+(y^2)/(100)=1 is semi-major axis b=10, semi-minor axis a=6