What is the axis x^2+y^2+4x-12y=0 ?

The axis x^2+y^2+4x-12y=0 is semi-major axis b=2sqrt(10), semi-minor axis a=2sqrt(10)

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axis x^2+y^2+4x-12y=0

axis

x^{2} + y^{2} + 4 x - 12 y = 0

semi - major axis b = 210, semi - minor axis a = 210

Solution steps

x^{2} + y^{2} + 4 x - 12 y = 0

Rewrite

x^{2} + y^{2} + 4 x - 12 y = 0

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{( 2 10 ) ^{2}} + \frac{( y - 6 ) ^{2}}{( 2 10 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 6), a = 210, b = 210

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, 6), b = 210, a = 210

\frac{x ^{2}}{5 ^{2}} + \frac{y ^{2}}{1 3 ^{2}} = 1

16 x^{2} + 9 y^{2} - 144 = 0

\frac{( x - 5 ) ^{2}}{49} + \frac{( y - 9 ) ^{2}}{25} = 1

\frac{x ^{2}}{56} + \frac{y ^{2}}{36} = 1

25 x^{2} + 16 y^{2} + 100 x + 96 y - 156 = 0

What is the axis x^2+y^2+4x-12y=0 ?
The axis x^2+y^2+4x-12y=0 is semi-major axis b=2sqrt(10), semi-minor axis a=2sqrt(10)