What is the axis (x^2)/3+(y^2)/9 =1 ?

The axis (x^2)/3+(y^2)/9 =1 is semi-major axis b=3, semi-minor axis a=sqrt(3)

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axis (x^2)/3+(y^2)/9 =1

axis

\frac{x ^{2}}{3} + \frac{y ^{2}}{9} = 1

semi - major axis b = 3, semi - minor axis a = 3

Solution steps

\frac{x ^{2}}{3} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{3} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 3 ) ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 3, a = 3

16 x^{2} + 25 y^{2} + 32 x - 150 y - 159 = 0

\frac{( x + 3 ) ^{2}}{25} + \frac{( y - 8 ) ^{2}}{16} = 1

4 x^{2} + 9 y^{2} - 16 x + 18 y - 11 = 0

x^{2} + \frac{y ^{2}}{49} = 1

\frac{( x + 6 ) ^{2}}{18} + \frac{( y + 3 ) ^{2}}{9} = 1

What is the axis (x^2)/3+(y^2)/9 =1 ?
The axis (x^2)/3+(y^2)/9 =1 is semi-major axis b=3, semi-minor axis a=sqrt(3)