What is the axis (x^2)/9+(y^2)/(16)=1 ?

The axis (x^2)/9+(y^2)/(16)=1 is semi-major axis b=4, semi-minor axis a=3

Popular >

axis (x^2)/9+(y^2)/(16)=1

axis

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

semi - major axis b = 4, semi - minor axis a = 3

Solution steps

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 3

25 x^{2} + 4 y^{2} - 50 x + 16 y - 59 = 0

\frac{( x - 4 ) ^{2}}{9} + \frac{( y + 2 ) ^{2}}{25} = 1

4 x^{2} + 24 x + 36 + 36 y^{2} - 360 y + 756 = 0

\frac{x ^{2}}{7} + \frac{y ^{2}}{16} = 1

\frac{( x - 1 ) ^{2}}{a ^{2}} + \frac{( y - 3 ) ^{2}}{b ^{2}} = 1

What is the axis (x^2)/9+(y^2)/(16)=1 ?
The axis (x^2)/9+(y^2)/(16)=1 is semi-major axis b=4, semi-minor axis a=3