What is x^2-9y^2+4x+18y-149=0 ?

The solution to x^2-9y^2+4x+18y-149=0 is Hyperbola with (h,k)=(-2,1),a=12,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-9y^2+4x+18y-149=0

x^{2} - 9 y^{2} + 4 x + 18 y - 149 = 0

(h, k) = (- 2, 1), a = 12, b = 4

Solution steps

x^{2} - 9 y^{2} + 4 x + 18 y - 149 = 0

Rewrite

x^{2} - 9 y^{2} + 4 x + 18 y - 149 = 0

in the form of a standard hyperbola equation

\frac{( x - ( - 2 ) ) ^{2}}{1 2 ^{2}} - \frac{( y - 1 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 1), a = 12, b = 4

4 y^{2} - 24 y - 2 x^{2} + 20 x = 22

x^{2} - y^{2} = 4 y

y^{2} - x^{2} = 4

9 + x^{2} - 3 y^{2} = 0

- 3 x^{2} + 2 y^{2} + 6 x - 7 y = 7

What is x^2-9y^2+4x+18y-149=0 ?
The solution to x^2-9y^2+4x+18y-149=0 is Hyperbola with (h,k)=(-2,1),a=12,b=4