What is ((x-8)^2)/9-((y+3)^2)/(16)=1 ?

The solution to ((x-8)^2)/9-((y+3)^2)/(16)=1 is Hyperbola with (h,k)=(8,-3),a=3,b=4

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((x-8)^2)/9-((y+3)^2)/(16)=1

\frac{( x - 8 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{16} = 1

(h, k) = (8, - 3), a = 3, b = 4

Solution steps

\frac{( x - 8 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 8 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 8 ) ^{2}}{3 ^{2}} - \frac{( y - ( - 3 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (8, - 3), a = 3, b = 4

\frac{x ^{2}}{9 + y ^{2}} = 1

9 x^{2} - 4 y^{2} - 54 x - 16 y + 29 = 0

x^{2} - 2 y^{2} = 1

4 x^{2} + 24 x - 2 y^{2} + 36 y = 36

x^{2} - y^{2} - 1 = 0

What is ((x-8)^2)/9-((y+3)^2)/(16)=1 ?
The solution to ((x-8)^2)/9-((y+3)^2)/(16)=1 is Hyperbola with (h,k)=(8,-3),a=3,b=4