What is 16x^2-25y^2+96x+544=0 ?

The solution to 16x^2-25y^2+96x+544=0 is Hyperbola with (h,k)=(-3,0),a=4,b=5

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16x^2-25y^2+96x+544=0

16 x^{2} - 25 y^{2} + 96 x + 544 = 0

(h, k) = (- 3, 0), a = 4, b = 5

Solution steps

16 x^{2} - 25 y^{2} + 96 x + 544 = 0

Rewrite

16 x^{2} - 25 y^{2} + 96 x + 544 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{4 ^{2}} - \frac{( x - ( - 3 ) ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, 0), a = 4, b = 5

9 x^{2} - 4 y^{2} - 54 x + 8 y + 113 = 0

25 x^{2} + 10922 x - 25 y^{2} - y^{2} = 1439

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{1} = 1

9 x^{2} - 4 y^{2} + 54 x + 8 y + 78 = 0

x^{2} - (y - 4)^{2} = 1

What is 16x^2-25y^2+96x+544=0 ?
The solution to 16x^2-25y^2+96x+544=0 is Hyperbola with (h,k)=(-3,0),a=4,b=5