What is ((x+1)^2)/(25)-((y-4)^2)/(144)=1 ?

The solution to ((x+1)^2)/(25)-((y-4)^2)/(144)=1 is Hyperbola with (h,k)=(-1,4),a=5,b=12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x+1)^2)/(25)-((y-4)^2)/(144)=1

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 4 ) ^{2}}{144} = 1

(h, k) = (- 1, 4), a = 5, b = 12

Solution steps

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 4 ) ^{2}}{144} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 4 ) ^{2}}{144} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{5 ^{2}} - \frac{( y - 4 ) ^{2}}{1 2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 4), a = 5, b = 12

2 x^{2} - 3 y^{2} = 6

x^{2} - 4 y^{2} - 4 = 0

16 x^{2} - 96 x - y^{2} - 2 y + 139 = 0

y = x^{2} - y^{2}

y^{2} = x^{2} + 196

What is ((x+1)^2)/(25)-((y-4)^2)/(144)=1 ?
The solution to ((x+1)^2)/(25)-((y-4)^2)/(144)=1 is Hyperbola with (h,k)=(-1,4),a=5,b=12